Oh, finding the x and y intercepts is like finding little treasures in your painting. To find the x-intercept, you set y to zero and solve for x. To find the y-intercept, you set x to zero and solve for y. Remember, there are no mistakes in mathematics, just happy little accidents.
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Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.