Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
Assuming the equation is 3x + y = 15, then the x-intercept is (5, 0) and the y-intercept is (0, 15).
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
I believe that you need an equation to solve for the x and y intercepts.
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
The 'x' and 'y' intercepts of that equation are both at the origin.
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
A circle represented by an equation x^2 + y^2 = r^2 or a circular object represented by an equation Ax^2 + By^2 = r^2 has 2 y-intercepts and 2 x-intercepts.
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49General Solutionset x=0 to find your y-intercept and set y=0 to find your x-intercept. That's how you will always find your intercepts, no matter what the equation is.Ex. So if you find that when x=0, y=a, then the y-intercept is at the point (0,a).Similarly, if you find that when y=0, x=b, then the x-intercept is at the point (b,0).You can solve any problem from here.
The y-intercept is c in the standard form. The x-intercept is -c/m.
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.