Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
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Oh, finding the x and y intercepts is like finding little treasures in your painting. To find the x-intercept, you set y to zero and solve for x. To find the y-intercept, you set x to zero and solve for y. Remember, there are no mistakes in mathematics, just happy little accidents.
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.
The quadratic (parabola) intercepts the x-axis when y = 0. So substitute y=0 into y = f(x). Then you can solve for the x-values by any number of ways: Factoring, completing the square, or Quadratic Formula. It may turn out that the values of x which satisfies y=0 are complex {have an imaginary component}, which will tell you that the parabola does not have an x-intercept.
2x-3y-4z=-24 has 3 potential intercepts. The x, y and z interceps. To find the x intercept we set y=z=0 This gives 2x=-24 or x=-12 To find the z intercept we set x=y=0 This gives -4z=-24 or z=6 Lastly to find the y intercept, x=z=0 so -3y=-24 and y=8 The x intercept is (-12,0,0), the y intercept is (0,8,0) and the z intercept is (0,0,6)