Best Answer

You are told that:

a + b + c = 123

You are also told that:

b = a + 1

c = a + 2

Therefore:

a + (a + 1) + (a + 2) = 123

3a + 3 = 123

3a = 120

a = 40

Therefore, the numbers are 40, 41 and 42.

Q: Find three consecutive integers whose sum is one hundred and twenty three?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

There is no set of three consecutive integers for 106.

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

There are no three consecutive odd integers who's sum equals 13.

20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22

The integers are -19, -18 and -17.

Related questions

The first four consecutive nonnegative integers. One-hundred and twenty-three with a leading zero.

There is no set of three consecutive integers for 187.

There is no set of three consecutive integers for 106.

There is no set of three consecutive integers whose sum is 71.

9240 is the product of the three consecutive integers 20, 21, and 22.

The sum of three consecutive integers is -72

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

10-11-12

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

There are no three consecutive odd integers who's sum equals 13.