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There is no set of three consecutive integers whose sum is 71.
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∙ 9y ago
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Find three consecutive odd integers whose sum is one hundred eighty three Enter your answer in a sequence like this 71 51 61?
Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.
The sum of the three consecutive numbers is 216?
The numbers are 71, 72 and 73.
Four consecutive integers whose sum is 290?
In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).
How do you find the sum of 216 with three numbers?
71 + 72 + 73 = 216
What two integers are between the square root of 71?
They are 8 and 9
The sum of three consecutive odd integers is 219?
* 71 * 73 * 75
Two consecutive integers whose sum is 71?
35 and 36
What is the equation for this The sum of two consecutive integers in 71?
The equation would be 35+36=71.
Find three consecutive odd integers whose sum is one hundred eighty three Enter your answer in a sequence like this 71 51 61?
Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.
The sum of the three consecutive numbers is 216?
The numbers are 71, 72 and 73.
What are the tree consecutive odd integers for 207 what are the integers?
The integers are 67, 69 and 71.
Three consecutive numbers have the sum of 210 what are the numbers?
The numbers are 69, 70, and 71.
What two consecutive integers equal 71?
35 and 36
What two consecutive integers equal 143?
71+72=143
How do you get the three consecutive odd integers of 219?
219/3 = 73 so the three are 73-2 = 71, 73 and 73+2 = 75.
Four consecutive integers whose sum is 290?
In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).
Find four consecutive integers whose sum is 290?
Let the first integer be x. then x + (x+1) + (x+2) + (x+3) = 290 4x + 6 = 290 4x = 284 x = 71 so the nanswer is 71+72+73+74 = 290
