Q: What is the sum of three consecutive integers of 71?

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Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

The numbers are 71, 72 and 73.

In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).

71 + 72 + 73 = 216

They are 8 and 9

Related questions

* 71 * 73 * 75

35 and 36

Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

The numbers are 71, 72 and 73.

Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.

The numbers are 69, 70, and 71.

The integers are 67, 69 and 71.

35 and 36

219/3 = 73 so the three are 73-2 = 71, 73 and 73+2 = 75.

71+72=143

In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).

There is no prime number between 60 and 80 that has a consecutive sum. The prime numbers between 60 and 80 are 61, 67, and 71, but none of them have consecutive sums.