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There is no set of three consecutive integers whose sum is 71.

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Q: What is the sum of three consecutive integers of 71?

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Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

The numbers are 71, 72 and 73.

In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).

71 + 72 + 73 = 216

They are 8 and 9

Related questions

* 71 * 73 * 75

35 and 36

The equation would be 35+36=71.

Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.

The numbers are 71, 72 and 73.

The integers are 67, 69 and 71.

The numbers are 69, 70, and 71.

35 and 36

71+72=143

219/3 = 73 so the three are 73-2 = 71, 73 and 73+2 = 75.

In order to do any consecutive integer problem, you should think of the numbers as x's. Here's what I did to solve this problem (and what you can do to solve future problems): (x) + (x +1) + (x +2) + (x + 3) = 290 4x + 6 = 290 4x = 284 x = 71, therefore the four numbers are 71, 72 (71 + 1), 73 (71 + 2), and 74 (71 + 3).

Let the first integer be x. then x + (x+1) + (x+2) + (x+3) = 290 4x + 6 = 290 4x = 284 x = 71 so the nanswer is 71+72+73+74 = 290