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There is no set of three consecutive integers for 187.

Q: What is three consecutive integers of 187?

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The numbers are -187 and -186.

9240 is the product of the three consecutive integers 20, 21, and 22.

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.

Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.

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The numbers are -187 and -186.

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The sum of three consecutive integers is -72

9240 is the product of the three consecutive integers 20, 21, and 22.

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

There are no three consecutive odd integers who's sum equals 13.

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).

No. There is no set of three consecutive even integers with a sum of 40.