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Q: Find three consecutive numbers where the smaller two numbers is 19 less than the square of the largest number?

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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

5,6,7

11,12,13

8,10,12

4, 6, and 8

3, 5, 7

4,6,8

8, 9, and 10

12, 13 and 14

1, 3, 5

16, 17 and 18

14, 15, 16

5, 6 and 7

4, 6, and 8

8, 10, 12

3, 5, 7

5, 6, 7

There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?

Five, six and seven. (Check the math, so you can be sure!)

The largest number is 9.

The three numbers are 6, 8, and 10. 102 - 8 x 6 = 52

The smaller number is 4.

There is no largest composite number. Nor is there a largest sequence of consecutive composite numbers - those sequences can become arbitrarily long.

the answer is 6

This isn't possible. They'd have to be even (8, 10, 12).