Q: Find three consecutive numbers with a sum of 159?

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The numbers are 52, 53 and 54.

52, 53 and 54.

The integers are 51, 53 and 55.

320

100 is approximately 62.9% of 159. To find this answer you could cross multiply. (159/100%)*(100/X) X = (100*100)/159 X = 62.89%

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The numbers are 52, 53 and 54.

157 + 159 = 316 157 x 159 = 24,963

Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.

52, 53 and 54.

The integers are 51, 53 and 55.

Two or more numbers are needed to find their LCM

159 is divisible by 1,3,53, and 159.

1, 3, 53, 159.

320

53, 106, 159, 212, 265, 318, 371, 424, 477 . . .

1 x 159, 3 x 53

Let the odd integers be , n, n+2 & n+4 Hence n + (n+2) + (n +4) = 471 Add LHS 3n + 6 = 471 Subtract '6' from both sides 3n = 465 Divide both sides by '3' n = 155 n + 2 = 157 n + 4 = 159 Hence the integers are 155,157 & 159.