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Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.

Q: Find 3 consecutive odd integers whose sum is 159?

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157 + 159 = 316 157 x 159 = 24,963

-125 - 159 = -284

159 as a decimal = 159.0

No. 159 is not evenly divisible by nine.

1, 3, 53, 159.

Related questions

The integers are 51, 53 and 55.

52, 53 and 54.

The numbers are 52, 53 and 54.

The sum of even integers cannot end with 9. why not

Let the odd integers be , n, n+2 & n+4 Hence n + (n+2) + (n +4) = 471 Add LHS 3n + 6 = 471 Subtract '6' from both sides 3n = 465 Divide both sides by '3' n = 155 n + 2 = 157 n + 4 = 159 Hence the integers are 155,157 & 159.

The numbers are 52, 53 and 54.

They are 79+80 = 159

157 + 159 = 316 157 x 159 = 24,963

That's two integers, not one.

100 is approximately 62.9% of 159. To find this answer you could cross multiply. (159/100%)*(100/X) X = (100*100)/159 X = 62.89%

To find 10 percent of a number, multiply the number by 0.1. In this instance, 0.1 x 159 = 15.9. Therefore, 10 percent of 159 is equal to 15.9.

The ratio of 159 percent of 159 % is 159:100 or 159/100 or 159 to 100.