There are 22 such numbers.
The total number of integers between 100 and 300 that are divisible by three is 66.
33 divisible by 3. 14 divisible by 7. 4 divisible by both. Total: 43
If a number is at least 5, and ends in "5" or "0", then it is divisible by 5. To further elaborate, If we are speaking of all numbers, the answer is an infinite number. If we limit it to positive integers, the answer is 50, 45, 40, 35, 30, 25, 20, 15, 10, 5, 0. Eleven total since 0 is a positive number.
Any multiple of 9. In other words, any number of the form 9 * n. Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678. The digits total 36. 36 is divisible by 9. So is 12,345,678.
I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138
The total number of integers between 100 and 300 that are divisible by three is 66.
To find the average of integers, add them all together then divide the total by the number of integers.
Add them up. Divide their total by the number of integers there are.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
To find out if a number is divisible by 3 add up all it's digest and check if the total is divisible by 3. to check if a number is divisible by 2 check if the last digit is divisible by 2. So one such number is 405.
There are a total of 14 numbers between 0 & 100 that are divisible by 7.
Add the digits. If the total is divisible by three, the original number is divisible by three. It's not and it's not.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
Add the digits of the number. If that total is divisible by nine, so is the original number. Example: 12,345,678 The digits total 36. 36 is divisible by 9. So is 12,345,678.
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
If a number is at least 5, and ends in "5" or "0", then it is divisible by 5. To further elaborate, If we are speaking of all numbers, the answer is an infinite number. If we limit it to positive integers, the answer is 50, 45, 40, 35, 30, 25, 20, 15, 10, 5, 0. Eleven total since 0 is a positive number.
33 divisible by 3. 14 divisible by 7. 4 divisible by both. Total: 43