Oh, dude, let me break it down for you. So, first, you find how many numbers are divisible by 6, which is 166. Then you find how many are divisible by 21, which is 47. But wait, don't forget to subtract the ones divisible by both 6 and 21, which is 7. So, the total is 166 + 47 - 7 = 206 integers that fit the bill. Easy peasy!
To find the integers between 1 and 1000 inclusive that are divisible by 6 or 21 but not by 7, we need to use the principle of inclusion-exclusion. First, we find the number of integers divisible by 6, which is 1000/6 = 166. Then, we find the number of integers divisible by 21, which is 1000/21 = 47. However, we must subtract the integers divisible by both 6 and 21 (which is 1000/42 = 23). Therefore, the total number of integers divisible by 6 or 21 is 166 + 47 - 23 = 190.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
9000 integers.
To find the number of even integers between 100 and 1000, we first determine the number of even integers between 1 and 1000, which is half of the total integers (since every other integer is even). So, 1000/2 = 500 even integers between 1 and 1000. Next, we subtract the number of even integers between 1 and 100, which is 50 (since every other integer is even in this range as well). Therefore, there are 500 - 50 = 450 even integers between 100 and 1000.
31.how do you solve?
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
There are 2828 integers between 1000 and 9999.
There are 10 palindromes divisible by 9 between 1000 and 9999.
333 integers.
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
There are 128 integers between 100 and 1000 that are divisible by seven.
There are 3168 such numbers.
750
If you are being inclusive, 1000 and 900. If not, 990 and 910.
From 1 (inclusive) to 1000(inclusive,) 750.
343!
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.