There are no numbers that are divisible by 21 but not by 7 so the "or 21" part of the question can be ignored.
There are 166 numbers between 1 and 1000 that are divisible by 6. However, 23 of those are also divisible by 7.
So 166 - 23 = 143 numbers.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
9000 integers.
31.how do you solve?
128!
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
There are 2828 integers between 1000 and 9999.
There are 10 palindromes divisible by 9 between 1000 and 9999.
333 integers.
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
There are 128 integers between 100 and 1000 that are divisible by seven.
There are 3168 such numbers.
750
If you are being inclusive, 1000 and 900. If not, 990 and 910.
From 1 (inclusive) to 1000(inclusive,) 750.
343!
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.