you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
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Oh, dude, let me break it down for you. So, first, you find how many numbers are divisible by 6, which is 166. Then you find how many are divisible by 21, which is 47. But wait, don't forget to subtract the ones divisible by both 6 and 21, which is 7. So, the total is 166 + 47 - 7 = 206 integers that fit the bill. Easy peasy!
9000 integers.
193 of them are divisible by one (or more) of the given numbers.
8 of them.
There are 2001 numbers.