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There are two values for y in the simultaneous equations: y = (-5) or 7

y = x - 3

y2 = 2x + 29

Substitute x for y and simplify to a quadratic equationin x:

(x-3)2 = 2x + 29

x2 - 6x + 9 = 2x + 29

x2 - 8x - 20 = 0

Using the quadratic equation (or just by looking here)

(x - 10)(x + 2) = 0

Where x = (-2) and y = -5

(-52) = (- 4) + 29

or x = 10 and y = 7

(72) = (20) + 29

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12y ago
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Q: Find y when y equals x minus 3 and y squared equals 2x plus 29?
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