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The centre is (-5, 3)

Q: Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?

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(-4,-6)

The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

no

x2 + y2 = 49

No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).

Related questions

The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

(-4,-6)

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5

x2 + y2 = 49

no

No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).

Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.

56

Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.

In order to take your circle and squash it horizontally to 1/2 of its original width (2),change the equation to4x2 + y2 = 16