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Q: For what real numbers is the square root of x greater than x?

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No. Negative numbers are real but their square roots are not.

Yes, they are.

No, it is not, because real numbers include negative numbers. The square root of a negative number is an imaginary number

-8x3 = -24 which has no square root in Real numbers. The square root of -24 is Â±4.898979*i where i is the imaginary square root of -1.

no, every number is a real number --- There are numbers that are not real numbers. They are called imaginary numbers, and have the property that when they are squared, the result is negative. The square root of -1 is called i, and the square root of any other negative number is i times the square root of the absolute value of the number. So the square root of -4 is 2i.

The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.

Neither. All irrational numbers are real numbers.Using the real number system you can't take the square root of a negative number, but if you're dealing with imaginary numbers then the square root of negative 3 is the square root of 3i

Yes, if the number whose square root we are taking is greater than 0. Only if you try to take the square root of a negative number will you get back an imaginary number. Square roots are often irrational, but that's different from real versus imaginary.

real numbers, irrational numbers, ...

no idea 666 ?

irrational

i, which is *defined* as the square root of -1, is imaginary, not real. The square root of -1 is i, the square root of -4 is 2i, the square root of -9 is 3i, etc. i, 2i, 3i, 4i, 5i, etc. = non-real numbers. 'Real' numbers are all of the numbers in the world: integers, rational numbers, irrational numbers, positive, negative, etc. Non-real (imaginary) numbers are numbers that exist only in theory such as the square root of a negative number, or the roots of an equation that never reaches the x-axis. (They are noted with the lowercase letter i for imaginary). This concept is very distant to most people outside of math classes.

Root 6 is an irrational [real] number.

Real Numbers cannot be the square root of a negative number. Real Numbers are not divided by zero. Basically, Real Numbers cannot be anything that is undefined.

Negative numbers do not have "real number" square roots.However, they will have two roots (when using imaginary numbers) as do other numbers, where a root including i(square root of -1) is positive or negative.

The square root of 8 is irrational and real.

You cannot in real numbers because the square of any number, negative or positive, is positive. However, -25 does have a square root in complex numbers: it is + or - 5i where i is the imaginary square root of -1.

Yes. The classic example is the square root of 2.

{natural, whole, integers, rational, real}

In real numbers, it has no root. If you get involved in imaginary numbers (essential for some branches of engineering design), it is 3.74j

There are two square root functions from the non-negative real numbers to either the non-negative real numbers (Quadrant I) or to the non-positive real numbers (Quadrant IV). The two functions are symmetrical about the horizontal axis.

0.1296714785 is a real number. All numbers that do not contain the square root of a negative number (represented by i) are real numbers.

Irrational Numbers which are a subset of Real Numbers which are a subset of Complex Numbers ...

3 is greater than the square root of 8.

38 is greater than the square root of 38