Formula for triginometry

Answer 1

Well, there are a few ways-

A) You can go with Sine, Cosine, Tangent (Spelling?)

And that works like this:

Sine=O/H (Opposite over Hypotenuse I believe)

Cosine=A/H (Adjacent side over Hypotenuse I believe)

Tangent=O/A (Opposite over Adjacent side I believe)

This is how you remember that:

Sine=Oscar/Had

Cosine=A/Hairy

Tangent=Old/A**

B) You can do it the easy way (how I do it)- A right triangle goes like this: The legs are A and B, and the hypotenuse is C. This is where we start.

A=B

A=C/ (the square root of 2)

B=A

B=C/ (the square root of 2)

C=A* (the square root of 2)

C=B* (the square root of 2)

All you math teachers out there- this works every time. I know it's not traditional, and there might be some building blocks it skips, but hey- it gets you to where you need to be.