Given the function f(x) = 2x + 3 and a = -1, we can find f(a) as follows:
f(a) = 2(-1) + 3
f(a) = -2 + 3
f(a) = 1
So, f(a) = 1.
To graph f(x) and 1/f(x), we can plot several points and connect them to visualize the functions. Here are some points for f(x):
For f(x):
When x = -2, f(x) = 2(-2) + 3 = -1
When x = -1, f(x) = 2(-1) + 3 = 1
When x = 0, f(x) = 2(0) + 3 = 3
When x = 1, f(x) = 2(1) + 3 = 5
When x = 2, f(x) = 2(2) + 3 = 7
Now, to find 1/f(x), we take the reciprocal of each f(x) value:
For 1/f(x):
When x = -2, 1/f(x) = 1/(-1) = -1
When x = -1, 1/f(x) = 1/1 = 1
When x = 0, 1/f(x) = 1/3 ≈ 0.333
When x = 1, 1/f(x) = 1/5 ≈ 0.2
When x = 2, 1/f(x) = 1/7 ≈ 0.143
Now, we can plot these points and connect them to obtain the graphs of f(x) and 1/f(x).
If the point (x,y) is on the graph of the even function y = f(x) then so is (-x,y)
To find F(-3) on a graph, first locate the x-axis and identify the point where x equals -3. Then, move vertically from this point until you intersect the graph of the function F. The y-coordinate of this intersection point represents F(-3). Make sure to clearly mark this point for reference.
1C is just above freezing point of water. 1F is WAY below freezing.
Select a set of x values and find the value of y or f(x) - depending on how the parabola is defined. These are the values that you need to graph.
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
The graph at the right shows a function, f, graphed on the domain 0 less equal x less equal 8. The section from A to B is a straight segment. The section from B to C is represented by y = (x - 5)². graph split Find the slope of the segment from A to B. Find the x-coordinate of the relative minimum value of the graph from B to C. Find the value of f (3) + f (4) + f (6) + f (7).
The fundamental theorem of calculus is F(b)-F(a) and this allows you to plug in the variables into the integral to find the are under a graph.
I am pretty sure it is 18.33333333
The second graph is shifted upwards by 4 units.
The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.
When the x coordinate is changed by adding a constant amount this is the same as translating (shifting) the graph of the function f(x) that amount parallel to the x-axis; if the amount is positive the graph is translated to the left, if it is negative it is translated to the right. As (7, -6) is on f(x), then under the translation f(x + 2), the graph is translated to the left (2 x-values), so the point (7-2, -6) which is the point (5, -6) is the corresponding point on the graph to (7, -6).
The Fibonacci sequence, discovered by Leonardo of Pisa is defined as follows:F(1) = 1F(2) = 1F(n+2) = F(n) + F(n+1) for n = 1, 2, 3, ...That is, the first two numbers in the sequence are 1, and after that every number is the sum of the two preceding numbers.