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Q: Given 3 consecutive integers with a sum of four times the second number write an algebraic equation?

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Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?

The sum of two consecutive integers will always be an odd number.

There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.

No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.

An algebraic number is a complex number which is the root of a polynomial equation with rational coefficients.

An algebraic integer is a number which is a root of a monic polynomial whose coefficients are integers.

The sum of any two consecutive integers must be an odd number. So this question is incorrect.

Consecutive integers are integers that follow in sequence. Each number is 1 more than the previous numbers.

No two consecutive integers can add up to 98.No three consecutive integers can add up to 98.But 23, 24, 25, and 26 can.

An algebraic equation or inequality can have a solution, an algebraic expression cannot. If substituting a number in place of a variable results in the equation or inequality being a true statement, then that number is a solution of the equation or inequality.

-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.

Integers are whole numbers therefore it follows that two consecutive integers can't result into a decimal number

The sum of two consecutive odd integers is an even number. There is no possible answer to this question.

An integer is a whole number. The two consecutive integers that equal 25 are 12 and 13.

The square root of 41 is an irrational , algebraic, real number. It is real, is the root of an polynomial equation with integer coefficients, but can not be expressed as a ratio of integers.

A rectangular number is a number which is the product of two consecutive integers.

I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).

There are none because two consecutive even integers would add up to an even number and the number given of 217 is an odd number.

Suppose the first number is 2x (rather than x, so that you force it to be even), where x is an integer. Then the next (consecutive) even number is 2x+2. So the equation is: 2x * (2x+2) = 48

not necessarily... An integer is a rational number, but so is any real number between consecutive integers.

consectutive basically means in order. So 4,5,6 is a series of consecutive integers

This is impossible, in mathematical terms. If you take two consecutive integers, then one of the integers must be odd and the other must be even. When you add an odd number to an even number, the result is always an odd number. Here, you said two consecutive integers add up to 26, which is an even number. Therefore, the answer is "No real solutions."

The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.

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