Given that dv/dt = a, you can take the integral of a, and get...
vt = a t + C. Substitute v0 for C, and you get vt = a t + v0
Assuming that the acceleration due to gravity is about -32 fps2, then the velocity after 2 seconds of an object down with an initial velocity of -20 fps is -80 fps.
To solve the second part of the question, "what is the velocity after falling 150 f?", you need to integrate again, and get...
xt = 1/2 a t2 + v0 t + C. Substitute x0 for C, and you get xt = 1/2 a t2 + v0 t + x0
Solve for t, with xt = 150, (300-150), v0 = -20, and x0 = 300, using the quadratic equation, and you get t = 2.28 s. (You also get t = -1.03 s, but you can ignore that because it is the solution for time prior to the release point.)
Go back to the first integral and plug in t = 2.28 s, and you get v = 92.9 fps.
This answer assumes no resistance from velocity in air. At 92.9 fps, you might get some effect, depending on the shape and density of the object, so the real answer is less than stated.
Acceleration = Final velocity - Initial velocity / time
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
the answer is 24-9 m/sec. yuor welcome
a = (v2 - u2)/2s where a is the acceleration between the initial point in time and the final point in time, u is the initial velocity v is the final velocity s is the distance travelled
This is a velocity question so u need to use uvaxt
The object opposes the air and while falling of the object the initial velocity will become zero , and the final velocity will have some value's this is how air will resist the velocity of falling object ...........
If you simply release an object, the initial velocity is always zero.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
Acceleration = Final velocity - Initial velocity / time
A projectile has an initial forward velocity.
The initial velocity is zero. In most basic physics problems like this one the initial velocity will be zero as a rule of thumb: the initial velocity is always zero, unless otherwise stated, or this is what you are solving for Cases where the initial velocity is not zero examples a cannon ball is shot out of a cannon at 50 mph a ball is thrown from at a speed of 15 mph etc
The graph is a straight line through the origin, with a slope of (9.8 m/s) per second.
the answer is 24-9 m/sec. yuor welcome
20.40
v = v0 + a t v = velocity (m/s) V0 = initial velocity at t = 0 (m/s) a = acceleration (9.81 for earth) t = time (sec)
a = (v2 - u2)/2s where a is the acceleration between the initial point in time and the final point in time, u is the initial velocity v is the final velocity s is the distance travelled
yes it does. u can calculate the final velocity of the falling object with the following eqn: initial potential energy= final kinetic energy or mgh = 1/2mv2 where m=mass, h = height,v=final velocity