the answer is 24-9 m/sec. yuor welcome
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
Data is insufficient. initial velocity is 0. final velocity is 30 mph. Need acceleration to use the formula v = u + at.
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
"8 seconds" is not a velocity.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
l2Math. l2Math.
if the objects distance travelled and time is given then speed=distance/time eg- distance travelled 50 mtrs time taken 5 seconds speed 50/5 =10m/s velocity=u(initial velocity 0 for free falling objects) + at(acceleration x time)
51 seconds.
After just over three and a quarter seconds.
.866 seconds
The answer for that one is 500 m/s