n + n+1 + n + 2 = 3n+3 = 3(n+1)
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
8 and 10. Since they are integers, they may not include decimals, so the answer is simply just the numbers you would find by adding or subtracting 1.
-10, -11, -12 -10 + -11 + -12= -33 written simply replacing the '+ -' s that just equal a '-' its simply: -10 - 11 -12= 33
Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.
There are two possible answers to your question depending on what mathematics course you are taking. The first answer involves the algebraic translation of "more than" to rewrite the question into an algebraic expression: 17 + 13. The second answer is simply the sum of the two integers: 30.
There are no two consecutive integers which sum to make 48. The closest you can get is if you drop the integer part of the problem and state simply that they have to have a difference of 1 between them. In which case it would be 23.5 and 24.5.
8 and 10. Since they are integers, they may not include decimals, so the answer is simply just the numbers you would find by adding or subtracting 1.
49+50+51=150 General rule for this kind of question: divide the number you're trying to obtain (150) by the number of integers you're allowed (3), and then simply add one and subtract one until you have the specified number of integers.
Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.Then they are, simply, two different integers. Any two positive integers will do, according to the specification.
-10, -11, -12 -10 + -11 + -12= -33 written simply replacing the '+ -' s that just equal a '-' its simply: -10 - 11 -12= 33
The boundary points of the integers is simply the integers.
That question has no answer, simply because there is no such thing as an "interger". 36 could be expressed as the sum of 10, 12, and 14 .
There are two possible answers to your question depending on what mathematics course you are taking. The first answer involves the algebraic translation of "more than" to rewrite the question into an algebraic expression: 17 + 13. The second answer is simply the sum of the two integers: 30.
9
You need at least two numbers to find a GCF. IF that's 3, 4 and 5, the GCF of consecutive nonzero integers is 1.
Start with an integer x. Since a consecutive integer will simply be 1 more than its neighbor, you can say that the three numbers you're trying to find are x, x + 1, and x + 2. So construct your equation using these three numbers as your consecutive integers: 4(x + (x + 1)) = 6(x + 2) 4(2x + 1) = 6(x + 2) 8x + 4 = 6x + 12 2x = 8 x = 4 Therefore, the three consecutive integers are 4, 5 (4 + 1), and 6 (4 + 2).
You simply add three consecutive integers (for instance 1,2,3 or 25,26,27) and take the square. Example: (12+13+14)2 = 392 = 1521. Or generally: (n + (n+1) + (n+2))2, where n is the first integer.