Start with an integer x. Since a consecutive integer will simply be 1 more than its neighbor, you can say that the three numbers you're trying to find are x, x + 1, and x + 2. So construct your equation using these three numbers as your consecutive integers:
4(x + (x + 1)) = 6(x + 2)
4(2x + 1) = 6(x + 2)
8x + 4 = 6x + 12
2x = 8
x = 4
Therefore, the three consecutive integers are 4, 5 (4 + 1), and 6 (4 + 2).
18, 20 and 22
Their sum is 99.
-1, 1 and 3
The integers would begin with 10.
The 3 consecutive odd positive integers are 7, 9 and 11.
9,10,11,12
10-11-12
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
18, 20 and 22
Their sum is 99.
-1, 1 and 3
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
1, 2 and 3 -1, -2, and -3 6 or -6
greater
The sum of three consecutive integers is -72
The integers would begin with 10.
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.