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Start with an integer x. Since a consecutive integer will simply be 1 more than its neighbor, you can say that the three numbers you're trying to find are x, x + 1, and x + 2. So construct your equation using these three numbers as your consecutive integers:

4(x + (x + 1)) = 6(x + 2)

4(2x + 1) = 6(x + 2)

8x + 4 = 6x + 12

2x = 8

x = 4

Therefore, the three consecutive integers are 4, 5 (4 + 1), and 6 (4 + 2).

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Q: Find 3 consecutive integers in which 4 times the sum of the first 2 is the same as 6 times the third?
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