53
78 multiplied by 53 is 4,134.
53 + 25 = 78
B. 53 neutrons. The number of neutrons in an atom is calculated by subtracting the number of protons from the atomic mass of the isotope. Since Iodine-131 has an atomic mass of approximately 131, and it has 53 protons, the number of neutrons is 131 - 53 = 78.
131
Iodine is element number 53 and and so has 53 protons. There are thus 131-53 = 78 neutrons
78/1.06 = 7800/106 = 3900/53
The atomic number of iodine, or I, is 53. Thus, neutral iodine would have 53 protons and 53 electrons. However, since we're talking about I-, we need to add an additional electron to this number, making it 54. Finally, the specific isotope of iodine in question, 131I, has 131 - 53 = 78 neutrons.
the solution to the equation -53 plus 1 -26 is -78.
134
78
78