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Q: How do you add -78 +53=?

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53

78 multiplied by 53 is 4,134.

53 + 25 = 78

The answer is, A 78(131 - 53 = 78)

131

78/1.06 = 7800/106 = 3900/53

78

52 add 26 = 78

Iodine is element number 53 and and so has 53 protons. There are thus 131-53 = 78 neutrons

the solution to the equation -53 plus 1 -26 is -78.

134

1540

The GCF is 1.

131I or Iodine

78

The atomic number of iodine, or I, is 53. Thus, neutral iodine would have 53 protons and 53 electrons. However, since we're talking about I-, we need to add an additional electron to this number, making it 54. Finally, the specific isotope of iodine in question, 131I, has 131 - 53 = 78 neutrons.

73

The GCF is 1.

53 I 131

Iodine has 53 protons and 53 neutrons. Iodine-131 isotope has 78 neutrons.

They add up to 53 thousandths which is 53/1000 or 0.053

127

83, 53 and 67 are prime, the rest are composite.

53

54 55 56 57...78 79