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To solve the equation X^3 + X^2 = 12, you'll need to find the values of X that satisfy the equation. Here's how you can solve it:
Rewrite the equation in standard form, setting it equal to zero:
X^3 + X^2 - 12 = 0
This equation is a cubic equation. To solve it, you can try factoring it or use numerical methods such as the Newton-Raphson method. In this case, factoring is a suitable method.
First, look for common factors that can be factored out from all the terms. In this case, you can factor out X^2:
X^2(X + 1) - 12 = 0
Now, you have a quadratic equation in the form (X^2 - 12)(X + 1) = 0. This equation can be factored further:
(X - √12)(X + √12)(X + 1) = 0
You now have three factors:
a) X - √12 = 0
b) X + √12 = 0
c) X + 1 = 0
Solve each of these equations for X:
a) X - √12 = 0
X = √12
b) X + √12 = 0
X = -√12
c) X + 1 = 0
X = -1
So, the solutions for X in the equation X^3 + X^2 = 12 are X = √12, X = -√12, and X = -1.
By 'Trial and error'.
x^3 + x^2 = 12
Try '1'
1^3 + 1^2 = 1 + 1 = 2 Not equal to '12'
Try '2'
2^3 + 2^2 = 8 + 4 = 12 The answer
Hence the value of 'x' is '2'.
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(x + y)(x + y)(x + y)
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You have to put your heart into it!
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X cubed plus y cubed equal 25?
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no
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x(x^2 + 1)
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How do you factor x cubed plus 10 x squared plus nine x?
x(x + 9)(x + 1)
