With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
7
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5
This cannot be solved for numerical answers. There must be 2 equations if there are 2 variables.
7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
7
5y - 2 = 28 - y 5y + y = 28 + 2 6y = 30 y = 30/6 y = 5
This cannot be solved for numerical answers. There must be 2 equations if there are 2 variables.
7y + 4 = 5y - 6Subtract 4 from each side:7y = 5y - 10Subtract 5y from each side:2y = -10Divide each side by 2:y = -5
If: 2x+5y = -10 Then by subtracting 2x from both sides: 5y = -2x-10 And dividing all terms by 5: y = -2/5x-2 which is now in slope intercept form
(-5, 2)
2 + 3 / 5y = 25 / 5y = 2(x both sides by 5y)5 = 10y(divide both sides by 10)0.5 = yy = 0.5Check...5/(5 x 0.5) = 25/2.5 = 2
Here's the equation: 3y=5y-13 To solve, add 13 to both sides, giving you 3y+13=5y 5y=3y+13 Now, subtract 3y from both sides, and divide by 2, giving you the answer. 2y=13 y=6.5 So, the solution is y=6.5.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
5y + 7 = 25y = -5y = -1
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
X = 0 (zero) Y = -1 (neg 1)