10x - 5y + 2x - 3y = 12x - 8y
x - 2y = 04x - 3y = 15From the first equation, x = 2y.SUBSTITUTING this value of x in the second equation,4*(2y) - 3y = 15 ie 8y - 3y = 15 or 5y = 15 so that y = 3and then, x = 2y gives x = 2*3 = 6Answer: x = 6, y = 3
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
5y = 2y+9 5y-2y = 9 3y = 9 y = 3
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
3y-8+5y = 2y-39 3y+5y-2y = -39+8 6y = -31 y = -31/6
3y+2y+4+1=80 5y+5=80 5y=80-5 5y=75 y=15
80 = 3y + 2y + 4 + 1 80 = 5y + 5 80 - 5 = 5y + 5 - 5 75 = 5y 75 / 5 = 5y / 5 15 = y
Presumably you want to know the value of y. 3y+2y+4+1 = 80 5y+5 = 80 5y = 80-5 5y = 75 y = 15
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15
-2 = 3y-18-5y 16=3y-5y 16=-2y y=-8
If: 3y+8 = 5y-20 Then: 3y-5y = -20-8 So: -2y = -28 And: y = -28/-2 => y = 14
(7x-3y) + (2x+5y) = 9x+2y