5y + 7 = 2
5y = -5
y = -1
(-5, 2)
This is Simultaneous equ'ns. 3x + 5y = -1 2x -5y = 16 Add the two eq'ns. This will eliminate 'y' Hence 5x = 15 x = 3 When x = 3 , substitute into either eq'n to yimnd 'y'. Hence 3)3) + 5y = -1 9 + 5y = -1 5y = -10 y = -10/5 = -2 So the solution in ( x,y) form is ( 3, -2).
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
y=(-1) x=(2)
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
(2, 3) is a solution only if it satisfies the equation. x + 5y = 4 (2) + 5(3) =? 4 2 + 15 =? 4 17 = 4 False Therefore, (2, 3) is not a solution to the given equation.
3
(2, 2)
7x + 5y 7(3) + 5(2) 21 + 10 = 31
Yes it is!
(2, 1)
3y+5.2=2-5y 8y=-3.2 y= -0.4