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Triangles have 3 sides and 3 interior angles that add up to 180 degrees

Quadrilaterals have 4 sides and 4 interior angles that add up to 360 degrees

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Q: How are triangles different from quadrilaterals l be specific?
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What the dimensions of 250 square feet?

The information given in the question does not give the shape of the area so it is impossible to answer the question. The most compact shape would be circular with a radius of just over 8.92 feet. With each of infinitely many polygonal shapes, there are infinitely many possible dimensions. Consider a rectangle. Let its length be L feet where L is any value > sqrt(250). Let is breadth be B = 250/L feet. Then area = L*B = L*250/L = 250 sq feet. But L can have infinitely many values and therefore the dimensions of the rectangle are indeterminate. For example, L = 25, B = 10 L = 250, B = 1 L = 25000, B = 0.01 and so on. And then there are non-rectangular quadrilaterals, triangles, pentagons, hexagons, ... .


What faces make up the net of a triangular prism?

Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.


What are is the naming of triangles?

if it is a perfect L, it is a right angle. if it is more then perfect, its an obtuse if it is less than perfect, /_, it is acute


How do you find the surface area of a rectangular pyramid?

For a rectangular pyramid (which is not a square bottom) you can not use the standard formula of Surface Area = B + 1/2 * P * s, because there is more than one slant height.A rectangular pyramid is made up of 1 rectangular baseand 4 triangles going up from the base to the top of the pyramid. The surface area is the area of all five parts added togetherThe first bit is a rectangle so you can find the area of it by multiplying its length times its width.Now we have four triangles, two of them will have a base which is the length of the pyramid and two will have a base which is the width of the pyramid.The area of a triangle is (1/2*bh), where b is the base (either length of width of the rectangle) and h is the slant height (distance from the base to the top of the pyramid).The triangles with base = length and the triangles with base = height will have different slant heights. There will be two triangles of each type so the area of all four triangles will be 2(1/2*ls1) + 2(1/2*ws2) = l*s1 + w*s2If you have been given both slant heights you have enough information to answer the question at this stage,You will have SA = l*w + l*s1 + w*s2(where l is length, w is width, s1 is the slant length of the triangles with base l, s2 is the slant length of the triangles with base w)If you do not have the slant lengths you will have to use the Pythagorean Theorem to find them, this will tell you the slant length of the triangle with base l, will be the square root of (w/2)2 + h2 where h is the height of the pyramid (distance from bottom to top through middle of pyramid) similarly the slant length of the triangle with base w will be the square root of (l/2)2 + h2


What are five quadrilaterals with area and perimeter?

Square, A = s2, P = 4 x s; Rectangle: A = L x W, P = 2 x (L + W); Parallelogram: A = L x W Rhombus: P = 4 x s Trapezium: Kite: You can fill in the gaps, and you have a bonus q/lateral...

Related questions

I am a 3D shape l have 4 faces l have 8 edges and 4 verticals faces are triangles what am l?

pyramid


What the dimensions of 250 square feet?

The information given in the question does not give the shape of the area so it is impossible to answer the question. The most compact shape would be circular with a radius of just over 8.92 feet. With each of infinitely many polygonal shapes, there are infinitely many possible dimensions. Consider a rectangle. Let its length be L feet where L is any value > sqrt(250). Let is breadth be B = 250/L feet. Then area = L*B = L*250/L = 250 sq feet. But L can have infinitely many values and therefore the dimensions of the rectangle are indeterminate. For example, L = 25, B = 10 L = 250, B = 1 L = 25000, B = 0.01 and so on. And then there are non-rectangular quadrilaterals, triangles, pentagons, hexagons, ... .


What faces make up the net of a triangular prism?

Four triangles and a square base! * * * * * Obviously answered by someone who does not know the difference between a prism and a pyramid. The net for a triangular prism is made up of two triangles and three rectangles. If the sides of the triangle are of length a, b and c and the length of the prism is l units, then the rectangles are a x l, b x l and c x l.


Is L a theorem is all about right triangles?

If you are referring to Pythagoras' theorem for right angle triangles then the theorem states that for any right angle triangle the square of its hypotenuse is equal to the sum of its squared sides.


Which letters can you use to make polygons by drawing just one line?

They are L and V which will take the form of triangles


What are is the naming of triangles?

if it is a perfect L, it is a right angle. if it is more then perfect, its an obtuse if it is less than perfect, /_, it is acute


What is the area of the parallelogram Round to the nearest tenth of a meter?

Can't do it Monique. The area depends on the size and angles of the sides; you've given us none of these. But I can give you an equation to plug in those numbers if you have them to come up with the area. generally area = A = area of the box + area of the triangles = L*l sin(alpha) + l^2 sin(alpha)cos(alpha); where the length of the parallel sides is L + l cos(alpha) and l is the diagonal length of each slanted side (of a triangle). Alpha is the angle of the slanted sides relative to a parallel side. NOTE: the "box" is the rectangle made up of the two parallel sides minus the lengths of the two triangles. Also note the two triangles fit together to form a smaller box; so we multiply its sides for the area the triangles contribute.


What is a wing of a building?

The phrase building wing refers to a specific section of a building. A building that is shaped like an L would have 2 different wings.


What is the length of the diagonal that bisects the rectangle into two triangles?

It is sqrt(L2 + B2) where L and B are the length and breadth of the rectangle.


How do you find the surface area of a rectangular pyramid?

For a rectangular pyramid (which is not a square bottom) you can not use the standard formula of Surface Area = B + 1/2 * P * s, because there is more than one slant height.A rectangular pyramid is made up of 1 rectangular baseand 4 triangles going up from the base to the top of the pyramid. The surface area is the area of all five parts added togetherThe first bit is a rectangle so you can find the area of it by multiplying its length times its width.Now we have four triangles, two of them will have a base which is the length of the pyramid and two will have a base which is the width of the pyramid.The area of a triangle is (1/2*bh), where b is the base (either length of width of the rectangle) and h is the slant height (distance from the base to the top of the pyramid).The triangles with base = length and the triangles with base = height will have different slant heights. There will be two triangles of each type so the area of all four triangles will be 2(1/2*ls1) + 2(1/2*ws2) = l*s1 + w*s2If you have been given both slant heights you have enough information to answer the question at this stage,You will have SA = l*w + l*s1 + w*s2(where l is length, w is width, s1 is the slant length of the triangles with base l, s2 is the slant length of the triangles with base w)If you do not have the slant lengths you will have to use the Pythagorean Theorem to find them, this will tell you the slant length of the triangle with base l, will be the square root of (w/2)2 + h2 where h is the height of the pyramid (distance from bottom to top through middle of pyramid) similarly the slant length of the triangle with base w will be the square root of (l/2)2 + h2


If A and B are two points in the plane the perpendicular bisector of line segment AB is the set of all points equidistant from A and B?

Let us consider a line l such that it is the perpendicular bisector of line segment AB and the line intersects at point C.Let us take any point on line l(say, D). Join A to D and B to D.Now we have two triangles ACD and BCD.Now, in triangles ACD & BCD, we haveCD = CD (Common side)�ACD = �BCD (Right angle)AC = BC (Since l bisects AB)According to Side-Angle-Side criteria: Both triangles are congruent.Since both triangles are congruent, therefore AD = BD.So, l is the set of all points equidistant from A & B.Hence proved.


What are five quadrilaterals with area and perimeter?

Square, A = s2, P = 4 x s; Rectangle: A = L x W, P = 2 x (L + W); Parallelogram: A = L x W Rhombus: P = 4 x s Trapezium: Kite: You can fill in the gaps, and you have a bonus q/lateral...