15 x 35 mm = 525 mm, which is also equal to 52.5 cm.
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
The product of 15, 2.8, and 0.8 is equal to 33.6 cm³.
Let the sides be: x-7 and x Using Pythagoras' theorem: (x-7)^2 +x^2 = 17^2 which is 289 Expanding brackets: x^2 -14x +49 +x^2 = 289 Collecting like terms and subtracting 289 from both sides: 2x^2 -14x -240 = 0 Using the quadratic equation formula: x has a positive value of 15 Therefore the perimeter is: (15-7)+15+17 = 40 cm
2 x 1.4 cm is a length of 2.8 cm.
NO ! You cubed the 'cm' part OK. Why did you not also cube the '15' part ? Look at this: You have a cube, 15 cm on each side. What is its volume ? Length = 15 cm Width = 15 cm Height = 15 cm Volume = (Length) x (width) x (height) (15 cm) x (15 cm) x (15 cm) = 3,375 cm3 An even slightly better way to look at it: (15 cm)3 = (15)3 x (cm)3 = (3,375) (cm3)
If that is the side length, just multiply 15 cm x 15 cm x 15 cm.
15 x 35 mm = 525 mm, which is also equal to 52.5 cm.
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
how big is 30 cm x 40cm
The product of 15, 2.8, and 0.8 is equal to 33.6 cm³.
1800cm3
20 cm x 15 cm = 300 cm2
Let the sides be: x-7 and x Using Pythagoras' theorem: (x-7)^2 +x^2 = 17^2 which is 289 Expanding brackets: x^2 -14x +49 +x^2 = 289 Collecting like terms and subtracting 289 from both sides: 2x^2 -14x -240 = 0 Using the quadratic equation formula: x has a positive value of 15 Therefore the perimeter is: (15-7)+15+17 = 40 cm
6 square centimeters - about the size of your thumb print.
2 x 1.4 cm is a length of 2.8 cm.
57cm X 54cm X 15 cm equals 7,156 square inches.