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Let the sides be: x-7 and x

Using Pythagoras' theorem: (x-7)^2 +x^2 = 17^2 which is 289

Expanding brackets: x^2 -14x +49 +x^2 = 289

Collecting like terms and subtracting 289 from both sides: 2x^2 -14x -240 = 0

Using the quadratic equation formula: x has a positive value of 15

Therefore the perimeter is: (15-7)+15+17 = 40 cm

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Q: What is the perimeter of a right angle triangle when one side is 7 cm shorter than the other side and has an hypotenuse of 17 cm?
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