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This must be a regular hexagon. Draw a height from the lower left vertex to the upper left vertex (2 units). Draw a horizontal diagonal thru the hexagon "left to right". These lines create 2 triangles on the left. A hexagon has angles of 60 degrees. Because the two extra lines are perpendicular so this means the triangles are 30-60-90 triangles. The altitude of these triangles is 1/2 the height of the hexagon, so these 1re 1 unit. 30-60-90 triangles have sides in the ratio of 1 to sq rt 3 to 2, since our side opposite the 60 degree angle is 1 unit, set up a proportion and the hypotenuse of the triangle is 2 (sq rt 3)/3. The other side is (sq rt 3)/3.

Now draw one triangle from the center of the hexagon to any 2 adjacent vertices. This creates an equilateral triangle. Its sides are all 2 (sq rt 3)/3. Draw an altitude, which will cut that triangle into another 30-60-90 triangle. The altitude of this triangle is 1 unit (by proportion or the Pythagorean theorem). So the area of this one triangle is 1/2 bh = 1/2 (2(sq rt 3)/3)(1) = (sq rt 3)/3.

Since there are 6 of these triangles, multiply by 6 to get the total area of the hexagon. (sq rt 3)/3 x 6 = 2(sq rt 3) answer.

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