The area of a hexagon with a perimeter of 12 units is about 10.4 units2
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
It is (3*sqrt(3)*s^2)/2 square units where the length of a side is s units long.
The answer depends on what the lengths s and a are meant to represent.
12Infinitely many all different:As it is only the area that matters, the perimeter can be any shape:An equilateral triangle (with sides approx 3.398 units)A square (with sides approx 2.236 units)A regular pentagon (with sides approx 1.705 units)A regular hexagon (with sides approx 1.387 units)A regular heptagonA regular octagonA regular nonagonA regular decagonA regular hendecagon (11 sided polygon)A regular dodecagon (12 sided polygon)A regular triskaidecagon (13 sided polygon)A regular 14 sided polygonA regular 15 sided polygonA regular 16 sided polygon...A circle (with radius approx 1.262 units)And there are also the non-regular shapes, eg an L shaped hexagon, a kite, a parallelogram which can have an area of 5 square units.
The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
what is the area of a regular hexagon with sides lengths of 12 inches long
The area of a hexagon with a perimeter of 12 units is about 10.4 units2
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
The area of a regular hexagon with a perimeter 120m is about 1039.2m2
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
The area of a regular hexagon with side length of 20cm is about 1039.23cm2
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
It is (3*sqrt(3)*s^2)/2 square units where the length of a side is s units long.
The answer depends on what the lengths s and a are meant to represent.
12Infinitely many all different:As it is only the area that matters, the perimeter can be any shape:An equilateral triangle (with sides approx 3.398 units)A square (with sides approx 2.236 units)A regular pentagon (with sides approx 1.705 units)A regular hexagon (with sides approx 1.387 units)A regular heptagonA regular octagonA regular nonagonA regular decagonA regular hendecagon (11 sided polygon)A regular dodecagon (12 sided polygon)A regular triskaidecagon (13 sided polygon)A regular 14 sided polygonA regular 15 sided polygonA regular 16 sided polygon...A circle (with radius approx 1.262 units)And there are also the non-regular shapes, eg an L shaped hexagon, a kite, a parallelogram which can have an area of 5 square units.
A hexagon has 6 sides. The area of a regular hexagon that has a perimeter of 60 cm is 259.81 cm squared.