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Q: How can 1 and 2 and 3 and 4 equal 24 using each number once?

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6^(7-5) = 36

(9-5)*(7-1)

(-6)*(-5+(-7)/(-7)) = 24

96 x 1/4 = 24

78 - (6 x 9) = 78 - 54 = 24

It is: (9-4-2) times 8 = 24

The smallest value Roman numeral using each symbol only once would be MCDXLIV = 1444

Try: (5-1) times (8-2) = 24

-8

It is: (5+13)/6 times 8 = 24

It can be done by: (9-5) times 6 times 1 = 24

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