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Q: How can 6 9 1 4 equal 24 using each number once?

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Any number using all ten digits once each, and ending in 0, 2, 4, 6 or 8 will do.

1+2+3^2*4 ^ means square, i.e. 3*3 Hope it's correct!

Five multiples of three that use each digit from 0 to 9 only once are: 12, 30, 45, 69, and 87.

210You could list the multiples of each number until you reach 210, but that is time-consuming and unnecessary. You can determine the LCM by prime factorization.Prime factorize each number.7: 1 x 710: 2 x 53: 1 x 3Multiply each prime factor the greatest number of times it occurs in any one factorization. Listing the factors from least to greatest: the most number of times 1 occurs is once, 2 occurs once, 3 occurs once, 5 occurs once, and 7 occurs once. Multiply the prime factors to get the LCM.LCM = 2 x 3 x 5 x 7 = 210

3 - 4 + 5 * 6 + 7 > 10

Related questions

6^(7-5) = 36

(9-5)*(7-1)

(-6)*(-5+(-7)/(-7)) = 24

It is simply: 1*2*3*4 = 24

78 - (6 x 9) = 78 - 54 = 24

It is: (9-4-2) times 8 = 24

The smallest value Roman numeral using each symbol only once would be MCDXLIV = 1444

Try: (5-1) times (8-2) = 24

-8

It is: (5+13)/6 times 8 = 24

It can be done by: (9-5) times 6 times 1 = 24

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