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Suppose the circle has centre (a, b) and radius r.Then, by definition, every point, (x, y) on the circle is at a distance r from (a, b).
That is, sqrt[(x - a)^2 + (y - b)^2] = r
Squaring both sides gives (x - a)^2 + (y - b)^2 = r^2.
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The radius of a circle = the diameter of the circle divided by 2
How does the area of a circle derived?
Area of a circle in square units = pi*radius2
What is a solution of an eqaution derived from an original equation that is not a solution of the original equation?
Extraneous solution
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When you make the circle bigger or smaller which number of the standard equation for a circle centered at the origin changes?
Standard equation for a circle centred at the origin is x2 + y2 = r2 where r is the radius of the circle. If you increase the size of the circle then the radius must increase, so r2 will be larger. eg a circle of radius 2 has the equation x2 + y2 = 4, if the radius increases to 3 then the equation becomes x2 + y2 = 9
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
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Is the equation for a circle a function?
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When you make the circle smaller which number in the standard equation for a circle centered at the origin decreases?
The radius of the circle decreases when you make the circle smaller.
How does the area of a circle derived?
Area of a circle in square units = pi*radius2
What is the exact radius of a circle with the circumference of thrity six meters?
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Equation for area of a circle?
area of a circle = pi*r2
What is a solution of an eqaution derived from an original equation that is not a solution of the original equation?
Extraneous solution
What is the equation for a circle with a center of (0 0) and a radius of 9?
The equation of the circle is: x^2 + y^2 = 81
Who derived the equation of motion of matter wave?
larokha
The center of a circle is located at c(3-13). The x-axis is tangent to the circle at (30). Find the equation of the circle?
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
The equation of the inner circle is x2 plus y2 equals 9 The radius of the outer circle is twice the radius of the inner circle What is the equation of the outer circle?
x^2+y^2=36
