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Q: If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?

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5

x2 + y2 = 25

x2 + y2 = 25

The equation of the circle is: (x-2)^2 + (y+3)^2 = 16

10. Equation of circle is x2 + y2 = r2. Consider: when x = 0 y2 must = 100 so y = 10 which describes a circle centre the origin, radius 10. Similarly when x = 10 y must be 0.

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5

x2 + y2 = 49

x2 + y2 = 25

x2 + y2 = 25

x2 + y2 = 36

x2 + y2= 16

x2 + y2 = r2, the equation of a circle centered at the origin. If you want to make the circle larger, increase the radius length.

The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.

Equation of circle: (x+2)^2 +(y+3) = 49

Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4

1.6667

Equation of circle: (x-3)^2 +(y-2)^2 = 49

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