Q: How can use a 2s fact and a 1s fact to find 3 x 8?

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3 times 8 it's only 24 always

I think 7x3 is = to 21

To get the 2s complement, find the 1s complement (by inverting the bits) and add 1. Assuming that number is [4-bit] binary it would be 1000. If it is preceded by 0s, as in, for example, 0000 1000, then it would be 1111 1000.

2s-4 equals 2(s-2). You can find the answer by factoring two out of both numbers.

One way is using the Twos (2s) complement; that is you find the binary representation of the positive number of -19, flip all the bits (0s to 1s and 1s to 0s), and finally add 1 to it.The positive bit of -19 is simply 19. It has a binary code of 0001 0011 (8 bits are required for this particular method). Flipping the bits, we get 1110 1100. Adding 1 (or 0000 0001) to our last answer, we get 1110 1101 which would be the binary representation of -19.

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3x8 with1s and 2s fact looks like this: =(2x8)+(1x8) =16+8 =24

3 times 8 it's only 24 always

3 * 8 = (2 + 1)*8 = (2 * 8) + (1 * 8)

I think 7x3 is = to 21

(1 x 3 ) x ( 2 X 4) = 24

1s + 1s + 1 = 2s + 1

In lithium, the orbital of highest relative energy is the 2s orbital. This is due to the fact that, in the electron configuration of lithium (1s^2 2s^1), the 2s orbital is farther from the nucleus compared to the 1s orbital, resulting in higher energy.

The 2s orbital is larger than the 1s orbital and is higher in energy.

the 1s orbital is closer to the nucleus and has a lower energy level compared to the 2s orbital. Additionally, the 2s orbital has a slightly higher energy, larger size, and can hold more electrons than the 1s orbital.

1s 2s 3s 3p 4s 3d 4p

1s and 2s orbitals differ in that 2s orbitals lie farther away from the nucleus in the next principle energy level. Other than that, they occupy the same shape of orbital, spherical, as indicated by the s.

lithium atom is just a ball it has 1s and 2s orbitals both of which are spheres the 1s is occupied by two electrons and the 2s one electron