(1 x 3 ) x ( 2 X 4) = 24
3x8 with1s and 2s fact looks like this: =(2x8)+(1x8) =16+8 =24
1) 3S = R 2) R+6= 2 (S+6)= 2S+12 ----> R=2S+6 1,2 )--> 3S = 2S+6 ---> S=6 & R= 3 x 6 = 18 Ralph is 18 & Sara is 6 .
75 25, 3 5, 5, 3
6+7
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
3 times 8 it's only 24 always
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
3 * 8 = (2 + 1)*8 = (2 * 8) + (1 * 8)
(1 x 3 ) x ( 2 X 4) = 24
2s2-s-15 = (2s+5)(s-3)
9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
If you mean: -4+3+2s = 15 then s = 8
For example, factor each denominator into prime factors. Then multiply all the prime factors, eliminate duplicates BUT ONLY if they appear in the factorisation of each of the numbers. NOT if a factor is duplicated in the same number. eg 36 = 2*2*3*3 and 48 = 2*2*2*2*3 Then two 2s and one 3 are duplicated. Note that the only two of the 2s are considered duplicates even though there are 4 of them in the factorisation of 48. So the LCD is [2]*[2]*[3]*3*2*2*2*2*3*3 where the duplicates to be removed are shown in square brackets. = 144.
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0