You need to use a table of standard scores.
Convert 7.9 million into standard value
68% of the scores are within 1 standard deviation of the mean -80, 120 95% of the scores are within 2 standard deviations of the mean -60, 140 99.7% of the scores are within 3 standard deviations of the mean -40, 180
Approx 84%.
T-scores have a mean of 50 and a standard deviation of 10. These values are fixed and do not change regardless of the distribution of T-scores.
78
Your question can not be answered. A tally of all scores in the class is necessary. These are then ranked (lowest to highest), and the percentiles identified. For more information, I suggest you look at percentiles under wikipedia.
If the standard deviation of 10 scores is zero, then all scores are the same.
Standard error, standard deviation, variance, range, inter-quartile range as well as measures based on other percentiles.
None.z-scores are linear transformations that are used to convert an "ordinary" Normal variable - with mean, m, and standard deviation, s, to a normal variable with mean = 0 and st dev = 1 : the Standard Normal distribution.
you multiply it by 10
The 25-75th percentiles of the ACT are from 24-29, so a middle 20 range or onwards should be pretty safe for admission.
All the scores are equal
If it is possible to assume normality, simply convert the desired score to a z-score, and look up the probability for that.
p10 eguals
Convert 7.9 million into standard value
This can only be done with the RAW scores, if it has been calculated to the individual Service's scores, it cannot be converted
68% of the scores are within 1 standard deviation of the mean -80, 120 95% of the scores are within 2 standard deviations of the mean -60, 140 99.7% of the scores are within 3 standard deviations of the mean -40, 180