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Let 'a' and 'b' be the length of one side and diagonal of a square.

Pythagorus's theorem as applied to a square: a^2 + a^2 = b^2.

Substituting a = 2 into the equation, we have b^2 = 2^2 + 2^2 = 8.

b = sqrt(8) = 2 * sqrt(2).

Q.E.D.

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Q: How can you express in radical form the length of the diagonal of a square whose sides are each 2?
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As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.


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