The diagonal length of a square with a 900 square foot area is: 42.43 feet.
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
It depends on 2.35m what: length of sides, diagonal, perimeter.
It depends on the relationship between the triangle and the square!
The area of a square is length (of a side) squared.
A diagonal bisecting a square creates two identical right triangles. The diagonal is the hypotenuse of a right triangles, so its length is the square root of the sums of the squares on the opposite two sides.
The length of a square with an area of 81 would be 9.
The square's diagonal is 11.314 cm
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
To find the area of a square with a diagonal of 14, we first need to determine the length of one side of the square. Using the Pythagorean theorem, we can calculate that the side length is 7√2. Then, we can find the area of the square by squaring the side length, which gives us 98 square units.
The diagonal is 14 inches.
If the area of a square is 100, then its side length is 10. If we draw in a diagonal, then we know by the Pythagorean formula that the diagonal's length is sqrt(10^2 + 10^2) = sqrt(200) = 10*sqrt(2).The square root of 2 is approximately 1.414, so the diagonal's length is approximately 10*1.414 =14.14* The diagonal of any square is the side length times (sq rt 2).
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
If, by diagnole, you meant diagonal, and that its length was 12√2 units, then the area is 144 square unit.
To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units. To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length. Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
The diagonal is 15.620 meters.