answersLogoWhite

0

Multiply them by 1/2 and you have half of the original fraction.

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

What is a hard question to do with fractions?

seven halves


Why is it necessary to convert two fractions into like fractions before adding and subtracting them?

Because think of like fractions as the same things.. you can subtract halves from halves for example, but what does it mean to take away a half from a third?By converting them into like fractions, we can add or subtract them easily.


Which of these words describes the relationship between the fractions 2 3rds and 3 halves?

Reciprocal


Why are halves a good choice for benchmark fractions for one and one third?

Because it rounds it


How do you do clock fractions?

a clock is divided into 12 parts, so you can shade in various fractions on the clock. Using the clock, you can display 12ths, 6ths, 4ths, 3rds, halves, and wholes.


How do you find volume with fractions?

You multiply the fractions


How much is 4.5 in fractions?

4 and a half = 4 1/2 Or 9 halves = 9/2 / is fraction sign


To find halves you divide by?

2


When subtracting fractions does the bottom have to be the same?

Yes the bottom has to be the same when subtracting fractions. The bottom (or denominator) tells you what you're working with. You cannot subtract thirds from halves just as you cannot subtract oranges from tissues.


How do you find the average of fractions?

To find the average of fractions, you first need to find a common denominator for all the fractions. Once you have the fractions with the same denominator, add them together to find the total. Then, divide the total by the number of fractions you added together to find the average. Remember to simplify the fraction if possible.


How do you find fractions from least to greatest?

you have to compare the common fractions


Where can you find fractions in the world?

you can find fractions on a recipe,shoes,signs,or notebooks as long as it is a fraction.