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How can you find width of a river using trigonometry with help of diagram?
Wiki User
∙ 9y ago
Can't draw diagrams on a text editor! At its simplest you need a compass and a long tape-measure. Establish a base line of known length along the bank between two points A & B.
Measure its compass bearing. Now from Point A take a bearing as near as possible at 90º to the base line to a distinct point on the far bank - a post, tree-trunk, distinctive boulder, say. Call it Point C. As long as it's visible from B as well.
Now take the bearing from B to C. Correct the bearings to find the actual angles of triangle ABC whose base is AB, "opposite side" is AC and hypotenuse is BC. Call angle ABC, "a".
Now you have a right-angled triangle in which AC is the river's width, W.
SO: W = (AB) Tan a
You can triangulate it with a non-right triangle but I'm afraid you'll have to refer, as I would, to the text-books for the appropriate formula!
OR: go out and buy or borrow a laser range-finder!
Wiki User
∙ 9y ago
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