3+3/.3
33/3 = 11
(3 + 3) / .3
The first three is 3000 and the second three is worth 300.
52 cards, 4 of them 3s... 4 in 52 = 1 in 13 = ~7.7%
3x7+4x2
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
PH4 has sp3 hybridization. This means that the phosphorus atom forms four sigma bonds using one 3s orbital and three 3p orbitals.
(3+3) / .3
The electron configuration of aluminum (atomic number 13) can be specified in three ways: the full electron configuration, the noble gas shorthand, and the orbital diagram. The full electron configuration is 1s² 2s² 2p⁶ 3s² 3p¹. The noble gas shorthand notation is [Ne] 3s² 3p¹, where [Ne] represents the electron configuration of neon, the nearest noble gas preceding aluminum. Lastly, an orbital diagram visually represents the distribution of electrons in the various orbitals.
To get 100 using eight 3s, you can use the following expression: ( (3 + 3) \times (3 + 3) + (3 + 3) ). This simplifies to ( 6 \times 6 + 6 = 36 + 6 = 100 ). Thus, by creatively combining the 3s, you can achieve the desired result.
Only if you subtract three.
There are three thirds (1/3s) in every whole, so there are six thirds in two wholes.