0.235 * 0.6891
= 0.1619385
What's to estimate?
The total decimal places in the multiplicands is the total in the answer.
It depends on what numbers you are multiplying and how many decimals places they each have. It doesn't always haveto move to the right.
If two decimal number have X and Y decimal places, respectively, then the raw product (before removing any trailing zeros) of the two numbers will have (X + Y) decimal places.
Both multiplication and division can be performed simply by moving the decimal point of the number: to the right if multiplying, to the left if dividing. E.g. for 10, you can move the decimal point by one place to perform the operation. Multiplication by 10: move decimal one place to the right (add zero if already a whole number). Division by 10: move decimal point one place to the left (one place in if a whole number).
two.
When you are multiplying two numbers with decimals, it's easy to do.First, multiply the numbers as if there were not decimals there:~5.8x8.7____~406464_____5046... then, count the number of places for the decimal points, and add them together. 5.8 = 1 decimal place, 8.7 = 1 decimal place, the two added together are 2 decimal places. So your answer, 5046 needs to have two decimal places; or 50.46(I'm sorry, I had to use a ~ to keep spacing correct... I'm having problems pushing a nbsp into the code... lol)
You do the multiplication in exactly the same way. The only extra thing is that when multiplying decimals, you need to place the decimal point (or decimal comma - depending on your country) in the correct position. If one number has, for example, 3 digits after the decimal point, and the other 4, you need to place the decimal point in the result (BEFORE eliminating unnecessary zeros) in such a way that there are, in this example, 7 digits (3 + 4) to the right of the decimal point.
It depends on what numbers you are multiplying and how many decimals places they each have. It doesn't always haveto move to the right.
If the two multiplicands have X and Y digits after the decimal place then their product (before removing any trailing 0s) has (X+Y) digits after the decimal point.
If two decimal number have X and Y decimal places, respectively, then the raw product (before removing any trailing zeros) of the two numbers will have (X + Y) decimal places.
Both multiplication and division can be performed simply by moving the decimal point of the number: to the right if multiplying, to the left if dividing. E.g. for 10, you can move the decimal point by one place to perform the operation. Multiplication by 10: move decimal one place to the right (add zero if already a whole number). Division by 10: move decimal point one place to the left (one place in if a whole number).
Using an estimate ensures that the answer is about right. With decimals where the decimal point should go is difficult for a lot of people, so an estimate of the answer ensures that it is put in the right place.
Hey awesome Question. The answer is no you do not have to line up the decimals when multyping only when adding and subtracting. The main thing is when you multiply make sure you put the decimal in the right place in your answer. YOu count how may places their are behind the decimals in BOTH numbers then you make sure their are that many places behind the decimal in you answer. :)
6 decimal place
If you have no clue about how decimals work then getting an estimate for the answer gives you an order of magnitude which can help in placing the decimal. But if you are even a bit clued up, estimating will not be necessary.
two.
It is the third digit after the decimal point.
When you are multiplying two numbers with decimals, it's easy to do.First, multiply the numbers as if there were not decimals there:~5.8x8.7____~406464_____5046... then, count the number of places for the decimal points, and add them together. 5.8 = 1 decimal place, 8.7 = 1 decimal place, the two added together are 2 decimal places. So your answer, 5046 needs to have two decimal places; or 50.46(I'm sorry, I had to use a ~ to keep spacing correct... I'm having problems pushing a nbsp into the code... lol)