7+7+7+7+7+7+7/7=43 7 times 6=42 plus 1 whole=43
The answer is 7s + 49.
5.28751 7s equals 37.
7s + 12 = 131 Therefore, 7s = 119 s = 119/7 Therefore, s = 17
32 - 21 = 11
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
7(r-s-6)
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
3
7z + 6s + s = 7z + 7s This can then be factorised using 7 as the factor: 7z + 7s = 7(z + s)
From left to right seventy thousand and seven.
37 divided by 7 equals 5 with a remainder of 2.
To find how many times 7 fits into 31, you can divide 31 by 7. Doing the calculation, 31 ÷ 7 equals approximately 4.43. This means there are 4 whole 7s in 31, with a remainder. Thus, 31 contains four 7s.