32 - 21 = 11
4r+3 = 3-2 4r = 3-3-2 4r = -2 Divide both sides of the equation by 4 to find the value of r: r = - 1/2
-13
3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4
3
The product is 33
4r+3 = 3-2 4r = 3-3-2 4r = -2 Divide both sides of the equation by 4 to find the value of r: r = - 1/2
-13
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
the value of x is 3
The value of -3 is -3. The value of x has no bearing on that!
3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4
a non examples is -3 equals -3
The value is 1 if (x, y) = (4, 3) and 0 otherwise.
3
The product is 33
here for least value X=2,y=3hence 2(3)-3(2)=0=0
-3