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Q: How can you write 44 as a product of prime numbers?

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It is: 2*2*11 = 44

Every counting number(except 1) can be expressed as product of prime numbers. So 44 can be expressed as product of prime numbers: 44 = 2x2x11 = 22x11.

It is: 2*2*11 = 44

It is: 2*2*11 = 44

As a product of its prime factors: 2*2*11 = 44

It is: 2*2*11 = 44

As a product of its prime factors: 2*2*11 = 44

44 = 2 x 2 x 11

44 = 2 x 2 x 11

The only prime number that is an even number is 2, and there is no prime number that can be multiplied by 2 that gives 44 as the product.

2 x 2 x 11 = 44

The prime numbers (factors) of 44 are: 2 and 11

To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.

The numbers 47 and 53 are prime.

Prime factorization is the finding which prime number multiply to get to make the original number. 44: 1, 2, 4, 11, 22, 44 Prime Factors: 2, 11 Prime Factorization: 2 x 2 x 11

I assume you are asking the question "what two prime numbers sum to 44". There may be other pairs of prime numbers that sum to 44, but 37 and 7 are both primes and their sum = 44.

It is: 2*2*11 = 44

2x2x11

Negative numbers don't have prime factorizations.

The prime numbers between 34 and 44 are: 37 41 43 The sum of these numbers is 37 + 41 + 43 = 121

The numbers are 43 and 44.

44 is an even number. All even numbers except 2 are composite numbers, so 44 is composite.

44,000,000,000

44,000,000

44 is equal to 11 x 2 x 2. The product of any set of prime factors of a number is equal to the number itself.