Q: How do you write 44 as a product of prime numbers?

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As a product of its prime factors: 2*2*11 = 44

It is: 2*2*11 = 44

The only prime number that is an even number is 2, and there is no prime number that can be multiplied by 2 that gives 44 as the product.

To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.

It is: 2*2*11 = 44

Related questions

2 x 2 x 11

Every counting number(except 1) can be expressed as product of prime numbers. So 44 can be expressed as product of prime numbers: 44 = 2x2x11 = 22x11.

As a product of its prime factors: 2*2*11 = 44

It is: 2*2*11 = 44

As a product of its prime factors: 2*2*11 = 44

The only prime number that is an even number is 2, and there is no prime number that can be multiplied by 2 that gives 44 as the product.

2 x 2 x 11 = 44

44 = 2 x 2 x 11

To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.

The prime numbers (factors) of 44 are: 2 and 11

Prime factorization is the finding which prime number multiply to get to make the original number. 44: 1, 2, 4, 11, 22, 44 Prime Factors: 2, 11 Prime Factorization: 2 x 2 x 11

I assume you are asking the question "what two prime numbers sum to 44". There may be other pairs of prime numbers that sum to 44, but 37 and 7 are both primes and their sum = 44.