(22/2) + 2 = 11 + 2 = 13
fourteen take away four and then add a four and times by (2 times 4)
You can make 10 using four 2s by applying arithmetic operations. One way to do this is: ( (2 + 2) \times (2 + 2) = 4 \times 4 = 16 ), which is incorrect. However, you can also achieve 10 by using the equation: ( 2 \times 2 + 2 + 2 = 10 ).
5 times 13 times 2 = 2 times 5 times 13 = 10 times 13 = 130
It is: 13/2 times 2 = 13
6 1/2 = 13/2 13/2 * 4/5 = 52/10 52/10 = 5 1/5
2 4/5 x 2/3 = 1 13/15
By dividing it until you stop with a number that can be divided by two using the .0's
I am guessing your problem is to compute 5 times 2 times 13. In this case, the property you are using the associative property.
It is: 6.5 times 2 = 13
To express (\log_{13}(145)) using (\log_{13}(2)), (\log_{13}(3)), and (\log_{13}(5)), first factor 145 into its prime components: (145 = 5 \times 29). Then, use the logarithmic property that states (\log_b(mn) = \log_b(m) + \log_b(n)). Since 29 can be expressed as (2 \times 3 \times 5), we have (\log_{13}(145) = \log_{13}(5) + \log_{13}(29)) and can derive (\log_{13}(29)) from the logs of 2 and 3 using their product.
2 TO 2OO FOUR TIMES
1/2 x 13/16 is 13/32