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Q: How do i put 3y 2-7y plus 3 - 5y plus 3-4y 2 In standard form?

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4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3

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Since the second one is a multiple of the first, it is automatically the LCM.

798 advance tickets and 1357 regular tickets were sold. Say x is the number of advance tickets and y is the number of regular tickets. So x + y = 2155 since 2155 is the number of tickets sold with x and y . We also know that 18x +34y = 60502 since x the advance tickets are $18 and y the regular tickets are $34 and the total proceeds are $60502. Alright now we can solve for either x or y. Let's solve for y. How do we do that? We get rid of x from the formula. So look at this. 18x = 60502 - 34y (just a modification of the second formula), x = 2155 - y (just a modification of the first formula) and then multiply that whole thing by 18 so 18x= 18(2155) - 18y which is 18x = 38790 - 18y. So we know 18x = 60502 - 34y and 18x = 38790 -18y so since 18x = 18x, 60502 - 34y = 38790 - 18y. Now we want the y all on the same side so let's add 34y to both sides and you get 60502 = 38790 + 16y. Then subtract 38790 from both sides and you get 60502 - 38790 = 16y which is 21712 = 16y which divided by 16 is 1357 = y. That's your number of regular tickets. Now then x + y = 2155 or x = 2155 - y so x = 2155 - 1357 = 798. So x is 798 and y is 1357. You can even plug it back into the problem and it works. 18x + 34y = 60502 which is 14364 + 46138 = 60502 and thankfully 14364 + 46138 does equal 60502.

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x + y = 57x - y = 11Add: 2x = 68x = 34y = 57 - x = 23Check: 34 - 23 ?=? 11 ? Yes. yay !

Some of my symptoms has been associated with the feeling that something is on the inside of my vagina, I most revist ny doctor, Also when standing to long I can become tired on the side in which the operation was performed. I am a 34Y/o women no children currently but with hopes of having some in the future. I can only pray that when it is time to have children things will be alright. However the procedure did stop the heavy menstrual flows.

This information gives us the equations: x + y = 17 x2 + y2 = 145 These equations are more difficult to solve. The solution to the equations is below. Possibly easier (at least with this specific question) is guessing and checking. The answers are 8 and 9. To check: 8 + 9 = 17 64 + 81 = 145 === === The equations we have are: x + y = 17 x2 + y2 = 145 Lets substitue by using the first equation: x = -y + 17 plug that in: (-y + 17)2 + y2 = 145 Now simplify: y2 - 34y + 289 + y2 = 145 Simplify a little more: 2y2 - 34y + 289 = 145 Create a quadratic equation: 2y2 - 34y + 144 = 0 Factor the polynomial (or use the quadratic formula): (y - 9)(2y - 16) = 0 So either: y - 9 = 0 so y = 9, Or 2y - 16 = 0 so y = 8. Note: Because both equations are symmetric (meaning x and y can be switched without changing anything, like x + y = 17 is the same as y + x = 17), we know that x and y are each either 8 or 9. Either way the answers are 8 and 9. Plug these into the original equations and they work. Otherwise, just plug the y values into the easiest equation to solve for x. So x + 8 = 17 so x = 9. The other option is x + 9 = 17 which leads to x = 8. The answers are (8,9) and (9,8). Either way, the two numbers to fill the requirements are 8 and 9.

oranges x apples y 5x+2y=72 1x+4y=48make it so that either the x value or the y value are the same2(5x+2y)=2(72)1x+4y=48here you can see how the y's are now the same10x+4y=1441x+4y=48subtract the bottom equation from the top one9x=96divide9x/9=96/9x=10 2/3substitute 10 2/3 for x in either of the original equations1x+4y=481(10 2/3)+4y=4810 2/3+4y=48subtract4y=48-10 2/34y=37 1/3divide4y/4=(37 1/3)/4y=9 1/3therefor, x is 10 2/3 y is 9 1/3money-wise, the oranges (x) are $10.67 and the apples (y) are $9.33

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