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How do i put 3y 2-7y plus 3 - 5y plus 3-4y 2 In standard form?
Kazzi1
If you mean: 3y^2-7y+3-5y+3-4y^2 then it is simplified to -y^2-12y+6
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∙ 9y ago
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What is 4y plus 3 greater than or equal to -9?
4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3
Find two integers whose product is -111 and who sum is -34?
-77
Find two numbers whose sum is 57 and whose difference is 11?
x + y = 57x - y = 11Add: 2x = 68x = 34y = 57 - x = 23Check: 34 - 23 ?=? 11 ? Yes. yay !
5 oranges and 2 apples cost 72.1 orange and 4 apples cost 48 how much do an orange and an apple cost?
oranges x apples y 5x+2y=72 1x+4y=48make it so that either the x value or the y value are the same2(5x+2y)=2(72)1x+4y=48here you can see how the y's are now the same10x+4y=1441x+4y=48subtract the bottom equation from the top one9x=96divide9x/9=96/9x=10 2/3substitute 10 2/3 for x in either of the original equations1x+4y=481(10 2/3)+4y=4810 2/3+4y=48subtract4y=48-10 2/34y=37 1/3divide4y/4=(37 1/3)/4y=9 1/3therefor, x is 10 2/3 y is 9 1/3money-wise, the oranges (x) are $10.67 and the apples (y) are $9.33
What is 12y squared minus 34y plus 28 divided by 3y plus 5?
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What is 4y plus 3 greater than or equal to -9?
4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3
Find two integers whose product is -111 and who sum is -34?
-77
How do you find the least common multiple of 6x to the power of y and 12x to the power of 4 y?
Since the second one is a multiple of the first, it is automatically the LCM.
Tickets are 18 in advance or 34 if purchased on the day of the game at half time it is announced that 2155 tickets were sold the revenues are 60502 how many tickets were sold?
798 advance tickets and 1357 regular tickets were sold. Say x is the number of advance tickets and y is the number of regular tickets. So x + y = 2155 since 2155 is the number of tickets sold with x and y . We also know that 18x +34y = 60502 since x the advance tickets are $18 and y the regular tickets are $34 and the total proceeds are $60502. Alright now we can solve for either x or y. Let's solve for y. How do we do that? We get rid of x from the formula. So look at this. 18x = 60502 - 34y (just a modification of the second formula), x = 2155 - y (just a modification of the first formula) and then multiply that whole thing by 18 so 18x= 18(2155) - 18y which is 18x = 38790 - 18y. So we know 18x = 60502 - 34y and 18x = 38790 -18y so since 18x = 18x, 60502 - 34y = 38790 - 18y. Now we want the y all on the same side so let's add 34y to both sides and you get 60502 = 38790 + 16y. Then subtract 38790 from both sides and you get 60502 - 38790 = 16y which is 21712 = 16y which divided by 16 is 1357 = y. That's your number of regular tickets. Now then x + y = 2155 or x = 2155 - y so x = 2155 - 1357 = 798. So x is 798 and y is 1357. You can even plug it back into the problem and it works. 18x + 34y = 60502 which is 14364 + 46138 = 60502 and thankfully 14364 + 46138 does equal 60502.
What two numbers when multiplied together equals 168 and when added together equals 34?
202
Find two numbers whose sum is 57 and whose difference is 11?
x + y = 57x - y = 11Add: 2x = 68x = 34y = 57 - x = 23Check: 34 - 23 ?=? 11 ? Yes. yay !
What are the symptoms after a dnc?
Some of my symptoms has been associated with the feeling that something is on the inside of my vagina, I most revist ny doctor, Also when standing to long I can become tired on the side in which the operation was performed. I am a 34Y/o women no children currently but with hopes of having some in the future. I can only pray that when it is time to have children things will be alright. However the procedure did stop the heavy menstrual flows.
If the sum of two numbers is 17 and the sum of their square is 145 - what is the larger number?
This information gives us the equations: x + y = 17 x2 + y2 = 145 These equations are more difficult to solve. The solution to the equations is below. Possibly easier (at least with this specific question) is guessing and checking. The answers are 8 and 9. To check: 8 + 9 = 17 64 + 81 = 145 === === The equations we have are: x + y = 17 x2 + y2 = 145 Lets substitue by using the first equation: x = -y + 17 plug that in: (-y + 17)2 + y2 = 145 Now simplify: y2 - 34y + 289 + y2 = 145 Simplify a little more: 2y2 - 34y + 289 = 145 Create a quadratic equation: 2y2 - 34y + 144 = 0 Factor the polynomial (or use the quadratic formula): (y - 9)(2y - 16) = 0 So either: y - 9 = 0 so y = 9, Or 2y - 16 = 0 so y = 8. Note: Because both equations are symmetric (meaning x and y can be switched without changing anything, like x + y = 17 is the same as y + x = 17), we know that x and y are each either 8 or 9. Either way the answers are 8 and 9. Plug these into the original equations and they work. Otherwise, just plug the y values into the easiest equation to solve for x. So x + 8 = 17 so x = 9. The other option is x + 9 = 17 which leads to x = 8. The answers are (8,9) and (9,8). Either way, the two numbers to fill the requirements are 8 and 9.
5 oranges and 2 apples cost 72.1 orange and 4 apples cost 48 how much do an orange and an apple cost?
oranges x apples y 5x+2y=72 1x+4y=48make it so that either the x value or the y value are the same2(5x+2y)=2(72)1x+4y=48here you can see how the y's are now the same10x+4y=1441x+4y=48subtract the bottom equation from the top one9x=96divide9x/9=96/9x=10 2/3substitute 10 2/3 for x in either of the original equations1x+4y=481(10 2/3)+4y=4810 2/3+4y=48subtract4y=48-10 2/34y=37 1/3divide4y/4=(37 1/3)/4y=9 1/3therefor, x is 10 2/3 y is 9 1/3money-wise, the oranges (x) are $10.67 and the apples (y) are $9.33
